Em 150 gramas de alumínio, quantos átomos deste elemento estão presentes? dados: mm(ai) = 27 gmol-¹ número de avogadro = 6,02 x 10²³

The question in English:
In 150 grams of aluminum, how many atoms of this element are present? 

Data: MM (AI) = 27 g mol-1 

Number of avogadro = 6.02 x 10²³



Moles (mol) = mass (g) / molar mass (g/mol)

Mass of Al is given as 150 g.
Hence, moles of Al = 150 g / 27 g/mol  = 5.56 mol

According to the Avogadro number, 1 mole of substance has 6.02 x 10²³ of particles.

Hence, 1 mole of Al = 6.02 x 10²³ of Al atoms
Then, atoms in 5.56 mol of Al = 6.02 x 10²³ mol⁻¹ x 5.56 mol
                                                = 3.34712 x 10²⁴

Hence, 150 g of  Al have 3.34712 x 10²⁴ of atoms.