Which chemical reaction falls under the study of electrochemistry? a) so3(g) + cao(s) --> caso4(s) b) zn(s) + cu^2+(aq) --> zn^2+(aq) + cu(s) c) so2(g) + h2o(l) --> h2so3(aq) d)caco3(s) --> cao(s) + co2(g)

B. Zn(s)+Cu^2+(aq)-> Zn^2+(aq)+Cu(s) 
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The chemical reaction b) Zn(s) + Cu^2+(aq) --> Zn^2+(aq) + Cu(s) falls under the study of electrochemistry as it involve ions dissolved in solution. these are electrolytic solutions capable of transferring eletrons.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.