Magine that an uncharged pith ball is brought into the electrostatic field of a charged rod. the side of the pith ball closest to the negatively charged end of the rod will a. be given a negative charge produced by the movement of electrons from the other end of the ball. b. be given a negative charge produced by the movement of electrons from the rod. c. not experience any induced charge and remain neutral. d. be given a positive charge produced by the movement of electrons to the other end of the ball.

option D. be given a positive charge produced by the movement of electrons to the other end of the ball.


Explanation:

This phenomenon is called electrostatic induction.

The excess of negative charge on the end of the rod will repel the electrons on the side of the pith ball that have been approached to it.

Then the electrons on the pith ball will move far away from this end with it will be left an excess of positive charge.

In this way the rod has induced that the ball acquires a positive charge on one end and a negative charge on the other end.

Density= mass/volume so 5.1 divided by 4.7 is  5.1 / 4.7 =1.08510638298round to the correct number of sig figs