What mass of carbon dioxide (co2) can be produced from 86.17 grams of c6h14 and excess oxygen?

2C6H14 + 13O2 ---> 6CO2 +14H2O

M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol

86.17 g C6H14 is 1 mole.

                             2C6H14 + 13O2 ---> 6CO2 +14H2O
from reaction        2 mol                         6 mol
from the problem  1 mol                         3 mol

M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Answer : 132.0 g CO2

Ibelieve its a because an empirical formula usually has a ch in it your options are a or b

You need to divided twenty four by a dozen them by the temperature it is getting cook by