What volume, in liters, of so2 is formed when 121 l of h2s(g) is burned? assume that both gases are measured under the same conditions?

H₂S gas burns in the presence of O₂ to form SO₂ and H₂O
complete reaction is as follows
2H₂S + 3O₂ ---> 2SO₂ + 2H₂O
stoichiometry of H₂S to SO₂ is 2:2
Avagadros law states that volume of gas is proportional to number of moles of gas. Therefore volume ratio between reactants and products is equal to the molar ratio.
hence, volume ratio of H₂S to SO₂ is 2:2
2 L of H₂S forms 2 L of SO₂
therefore 121 L of H₂S forms 121 L of SO₂
volume of SO₂ produced is 121 L

 The  volume  in liters,of so2  formed when 121 l  of H2S (g)  is burned   is   121  liters

 Explanation

write the equation for  reaction
2H2S  +3 O2  = 2SO2  +2 H2O

from the above balanced  equation there  is   2  moles of So2  formed  from   burning  2  moles  of 2 H2O

 by use  of stoichiometric  ratio  which is  1 :1   the  volume  SO2  = 121 l

The correct answer is c

You know how the first one if filled up like the objects do the same but with the other categories