Calculate the number of grams of oxygen present in 1.75 moles of calcium carbonate

The number  of grams  of oxygen  present  in  1.75  moles  of  calcium   carbonate    is  84  grams

    Explanation

mass  =  moles x molar mass
molar  mass  =  16 g/mol

find the  number  of moles of  oxygen  in calcium  carbonate as below
formula  of    calcium  carbonate  is CaCO3

 from the  formula above    have   three(3)  atoms  of  oxygen

therefore  the moles  of  0xygen =  3 x 1.75 =5.25  moles

mass of  oxygen  is therefore = 5.25  moles  x16g/mol  =  84 grams  of  oxygen

Ithink that the answer is b