If 14.5 grams of silver nitrate (molar mass =169.88g/mol) reacts with aluminum chloride. how many grams of aluminum nitrate (molar mass = 213.01g/mol) are formed

3AgNO3 + AlCl3 ----> Al(NO3)3 + 3AgCl



The answer is 6.06g of Al(NO3)3 is formed.

Cause its being chemically applied?

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na