An aqueous solution is analyzed and found to contain potassium ions and sulfite ions. write the equation for the dissolution of the salt that produced this solution. if the solution contains 0.700 mol of potassium ions, how many moles of sulfite ions are present? answer in units of ol.

1) The dissolution of the salt potassium sulfite:
K₂SO₃(aq) → 2K⁺(aq) + SO₃²⁻(aq).
Potassium has +1 charge because it lost one electron to accomplish stabile electron configuration of noble gas argon.
2) From dissolution reaction: n(K⁺) : n(SO₃²⁻) = 2 : 1.
n(K⁺) = 0.700 mol.
0.700 mol : n(SO₃²⁻) = 2 : 1.
n(SO₃²⁻) = 0.700 mol ÷ 2.
n(SO₃²⁻) = 0.350 mol; amount of sulfite anions.