Given the equation: __ca 2+ (aq) + __po43− (aq) → __ca3(po4)2(s) when the equation is correctly balanced, the sum of the total charge of the reactants is

(aq) + (aq) ⇒

The sum of total charges of the reactant = 3×(2+) + 2×(3-)
                                                                 = 6 + (-6)
                                                                  =0

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