Astudent balances the following redox reaction using half-reactions. al+mn2+-> ai3+mn2 how many electrons will be lost in all? 1 2 5 6

The  number   of  electron lost  are  2

Explanation
 Al  +Mn^2+→   Al^3+  + Mn2

from equation above   the oxidation of  Al move  from  zero( 0)  to  positive  three (3^+), while  the oxidation of  Mn move from oxidation state   positive  two( 2^+)   to   Zero.   Since the oxidation for Mn  is reduced from 2^+ to 0   the   number of electron lost are 2

1. o2(g)as a product