What is the percent yield of h2o if 87.0 g of h2o is produced by combining 95.0 g of o2 and 11.0 g of h2

The percent yield of water is 87.87%.

Explanation:

Experimental yield of water =  87.0 g

Theoretical yield of water will be calculate as:

Moles of oxygen gas :

Moles of hydrogen gas:

2 moles of hydrogen reacts with 1 mole of oxygen then, 5.5 moles of hydrogen will react with 2.75 moles of oxygen gas.

Hydrogen gas is in limited amount hence will act as limiting reagent in the reaction.

According to reaction, 2 moles of hydrogen reacts gives 2 mole of water

Then, 5.5 moles of hydrogen gas will give:

of water

Theoretical yield of water = 5.5 × 18 g/mol=99 g

Percentage yiled:

The percent yield of water is 87.87%.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

the answer is c. nacl