What is the theoretical yield in grams for this reaction under the given conditions? 1.12 g h2 is allowed to react with 9.72 g n2, producing 1.00 g nh3.?

H₂ is the limiting reactant and the theoretical yield is 6.31 g of NH₃.

In order to determine the theoretical yield, the following steps must be done:

STEP 1. The balanced chemical equation for the given reaction is:

3 H₂ + N₂ → 2 NH₃

STEP 2. Determining the Limiting Reactant

The Limiting Reactant (LR) will produce fewer moles of the products. To check  which of the reactants H₂ or N₂ is the LR ,do dimensional analysis:

Since H₂ produces fewer moles of NH₃, then it is the limiting reactant. Its given amount will be used to determine the theoretical yield.

STEP 3. Determining the Theoretical Yield

From Step 2 it is known that 0.3704 moles of NH₃ will be produced. This needs to be converted to grams.

Since the answer only requires 3 significant figures, the final answer is 6.31 grams NH₃.

Keywords: stoichiometry, theoretical yield

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.