To prepare 350ml of alcohol 35% using alcohol 10% and alcohol 70%, how many milliliters of each are needed?

10%(x)+70%(350-x)=35%(350)
        .1(x)+.7(350-x)=.35(350)
        (.1x)+(245-.7x)=(122.5)
              .1x+245-.7x=122.5
                       .1x-.7x=-122.5
                            -.6x=-122.5
                             .6x=122.5
                                 x=204.1667 OR 204 and 1/6

350-x=145.8333 OR 145 and 5/6

Therefore in order to prepare 350ml of a 35% alcohol one would need 204.17 OR 204 and 1/6 ml of the 10% alcohol and 145.83 OR 145 and 5/6 ml of the 70% alcohol.

Is there a diagram/picture you can provide? it seems this question goes along with a

Sorry i dont understand the question can you rephase it?