Agas is contained in a thick-walled balloon. when the pressure changes from 2.95 atm to atm, the volume changes from 7.456 l to 4.782 l and the temperature changes from 379 k to 212 k

Let's assume that the gas in the balloon is an ideal gas.

We can use combined gas law,

 PV/T = k (constant)

Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.

For two situations, we can use that as,

P₁V₁/T₁= P₂V₂/T₂

P₁ = 2.95 atm

V₁ =  7.456 L

T₁ = 379 K

P₂ = ?

V₂ = 4.782 L

T₂ = 212 K

By applying the formula,

 2.95 atm x 7.456 L / 379 K = P₂ x 4.782 L / 212 K

                                       P₂ = (2.95 atm x 7.456 L x 212 K) / (379 K x 4.782 L)

                                       P₂ = 2.57 atm

Hence, the answer is 2.57 atm.

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