Acalorimeter is filled with 250.0 g of water at 24.6oc. a 60.0 g sample of a metal at 100.0 oc is dropped in this calorimeter and causes the temperature to increase a total of 4.5oc. what is the specific heat of the metal (in j/g°c)? ignore the calorimeter in this problem

Answer : The specific heat of metal in this case will be 0.411 J/g°C

Explanation : Specific heat can be calculated by using the formula 
Q = CmΔT

where Q is heat added which is 100 here
C is specific heat which needs to be found
m is mass of the metal
and ΔT is the temperature change

on substituting we get,

100 =  x . 60 . 4.05

so, x = 0.411 

Ifound this on google “laws of chemical combination. it states that matter can neither be created nor destroyed. it stated that a given compound always contains exactly the same proportion of elements by weight.” i hope this you for what your looking for.