What is the empirical formula for this compound 50.05% sulfur and 49.95% oxgyen by mass?

1)
Lets take 100g of this compound.
It contains 
50.05 g S and 49.95 g O.

2)
M(S) = 32.06 g/mol
M(O) = 16.00 g/mol

50.05 g S*1mol S/32.06 g S= 1.56 mol S
49.95 g O*1mol O/16.00 g O =3.12 mol O

3) S:O =
=1.56 mol S : 3.12 mol O = (1.56 mol /1.56 mol ) : (3.12 mol /1.56 mol) =1:2

(mol S):(mol O)=1 : 2

SO2

The answer should be c.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na