Aballoon that had a volume of 3.5 l at 25.0 c is placed in a hot room at 40.9 c. if the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the room?

V1/T1 = V2/T2

V1= 3.5 L

T1 = 25 +273=298 K

T2 = 40.9 + 273 = 313.9 K

V2- ?

3.5 L/298 K= V2/ 313.9 K

V2 = (3.5 L*313.9 K)/298 K ≈ 3.69 L

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j