How many moles of o2 should be supplied to burn 1.82 mol of c3h8 (propane) molecules in a camping stove?

C3H8 + 5O2 > 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol

x=(1.82*5)/1 = 9.10 mol CO2

explanation: no but i do not usually comment

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