For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m ; [h2] = 0.420 m ; [n2] = 0.800 m . give the equilibrium constant expression and use it to calculate the constant. 2 nh3(g) 3 h2(g) + n2(g)

Equation for the decomposition of ammonia :

2NH3->N2+3H2

Equilibrium constant for this equation will be:

Kc=[N2]([H2]^3)/[NH3]^2

As given Concentration of N2=0.800 M

Concentration of H2=0.420 M

Concentration of NH3=0.250 M

So Kc=([0.420]^3) *(0.8)/([0.250]^2)

= 0.9483264

so equilibrium constant will be:

0.9483264

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answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.