8. given the balanced chemical equation br2 + 2 nai -> 2 nabr + i2 how many moles of sodium bromide (nabr) could be produced from 0.172 mol of bromine (br2)?

Since we are already given the balanced equation:

→

We can derive the molar ratios as: 1:2:1:1

That being said, we are given 0.172 moles of bromine (), so it has a ratio of 1:1 with sodium bromide ().

So we can take from that ratio, that when 0.172 moles of bromine are used, we are, in turn, going to get 0.172 moles of sodium bromide produced.