A36 gram sample contains 28 grams of fe and 8 grams of oxygen. determine the percent composition for each of the elements.

The sample contains both Fe and oxygen

The mass of the sample is 36 g

28 g are Fe and 8 g are O

So to find the percent composition we can calculate using the following formula

Percent composition of the element = mass of the element / mass of the sample x 100%

Percent composition of Fe = 28 g / 36 g x 100 % = 77.8%

Percent composition of O = 8 g / 36 g x 100 % = 22.2%

The percentage composition for each of the elements is

Fe =77.8 % oxygen= 22.2%

calculation

% composition = mass of the element/total mass x100

total mass = 36g

The % composition of Fe = 28/36 x100 = 77.8%

The % composition of oxygen = 8/36 x100 = 22.2%

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8