If the compound methane (ch4) has no lone pairs, it would take which shape? a. linear compound b. tetrahedral compound c. trigonal planar compound d. trigonal bipyramid

Answer : The correct option is, (B) Tetrahedral compound

Explanation :  

Formula used:

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the molecule.

The number of electrons are 4 and there is no lone pairs present on the central carbon atom that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.

Hence, the shape of the given compound is, tetrahedral.

the correct answer to this question is 2

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied