Achemical company makes pure silver by reacting silver nitrate with zinc. the company needs to make 800 grams of pure silver for a client. they have 599 grams of zinc and 1500 grams of silver nitrate will the make enough silver to fill the order

The reaction between zinc and silver nitrate is

Moles of Zn = m /M = 599 /65 = 9.2 mol

Moles of AgNO3 = m /M = 1500 /169 = 8.87 mol

Silver nitrate is reacting completely to give silver

Thus, moles of Silver nitrate is equivalent to silver = 8.87

For mass of silver produced

m /M = 8.87 = m /107

m = 949.24 g

Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g

it's filtration, but this is an assumption so my apologies if i got this

so what is the problem with your lab report and whats the subject of the lab report? i will you