How would you use ir and 1h-nmr spectroscopy to distinguish between these two isomeric compounds? isomer a.4-methoxypentanoyl chloride isomer b.6-chlorohexanoic acid g?

A carboxyl group is present in 6-chlorohexanoic acid having IR peak between 1690 -1760 Cm-1 whereas in 4-methoxypentanoyl chloride , a carbonyl group is present as oyl chloride as having peak between 1715 -1745 Cm-1.

Now, in 4-methoxypentanoyl chloride , the peaks are (1 H, m) , (2 H, t ), (2 H , q ) whereas in 6-chlorohexanoic acid , the peaks are (2 H, m), (2 H, m ), (2 H , t )

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

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