Determine the identity of the daughter nuclide from the positron emission of 6832ge. determine the identity of the daughter nuclide from the positron emission of

- The daughter nuclide is Gallium with atomic number 31 and mass number 68.

Explanations:- Positron emission is also known as beta plus decay. In this type of radioactive decay in which a proton changes into neutron and a positron and electron neutrino are released.

As the proton changes into neutron, mass number remains same but the atomic number decreases by one unit.

The given element is Ge with atomic number 32 and mass number 68. Mass number decreases by one unit means the atomic number of the daughter nuclide would be 31 and it is Gallium.

The equation could be written as:

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

answer; talc and gypsum;