What is the ph of a solution prepared by mixing 25.00 ml of 0.10 m ch3co2h with 25.00 ml of 0.020 m ch3co2na? assume that the volume of the solutions are additive and that k a = 1.8 × 10-5 for ch3co2h?

- The pH of the buffer solution will be 4.04 .

Solution:- Sodium acetate added to acetic acid makes a buffer solution and the pH of buffer solution is easily calculated by using Handerson equation:

We are adding 25.00 mL of each, so the total volume of the buffer solution will be 50.00 mL.

We can calculate the concentration of base which is sodium acetate and acid by using dilution equation:

for base:

Similarly, for acid:

pKa is calculated from given Ka value as:

pKa = 4.74

Let's plug in the values in Handerson equation:

pH = 4.74 - 0.70

pH = 4.04

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o