How many moles of calcuim oxide are needed to react with an excess of water to form 370g of calcuim hydroxide

-

5

Explanation:-

Chemical formula for calcium oxide = CaO

Chemical formula of water = H2O

Chemical Formula of Calcium Hydroxide = Ca(OH)2

Mass of Ca(OH)2 = 370g

Molar mass of Ca(OH)2 = 40 x 1 + ( 16 x 1 + 1 x 1 ) x 2

= 74 g mol-1

Number of moles of Ca(OH)2 = 370 g / 74 g mol-1

= 5 moles

The balanced chemical equation for this process is

CaO + H2O --> Ca(OH)2

From the equation we see

For 1 mol of Ca(OH)2 to form, 1 mol of CaO is needed to react.

For 5 mol of Ca(OH)2 to form, 5 x 1 / 1 = 5 mol of CaO is needed to react.

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.