How many moles of magnesium hydroxide are needed to produce 74.7 milliliters of water, if the density of water is 0.987 g/ml? show all steps of your calculations as well as the final answer. hno3 + mg(oh)2 → h2o + mg(no3)2?

Given volume of water produced in the reaction = 74.7 mL

Density of water = 0.987 g/mL

Calculating the mass of water =

Moles of water produced =

The balanced chemical equation between nitric acid and magnesium hydroxide is,

1 mol Magnesium hydroxide gives 2 mol water.

Moles of Magnesium hydroxide =