Iron oxide can be reduced to metallic iron by heating it in the presence of carbon balance the following equation then determine the ratio of c to f e in the reaction

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3 C + Fe2O3 --> 2 Fe + 3 CO

3 : 2 ratio

Explanation:-

The chemical formula of Iron Oxide = Fe2O3

The symbol for Carbon = C

The symbol for Iron = Fe

The equation for this reaction becomes

C + Fe2O3 --> Fe + CO

On the left side there are 2 Fe

To make 2 Fe on right side we multiply Fe by 2.

C+ Fe2O3 --> 2 Fe + CO

There are 3 O on the left side. To make 3 O on right side we multiply CO by 3.

C + Fe2O3 --> 2 Fe + 3 CO

Now we have 3 C on the right side. To make 3 C on the left we multiply C by 3.

3 C + Fe2O3 --> 2 Fe + 3 CO

Thus balanced chemical equation for this reaction is

3 C + Fe2O3 --> 2 Fe + 3 CO

So in the balanced reaction we have 3 C and 2 Fe.

∴ The ratio of C to Fe is 3 : 2

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%