How many moles of nitrogen gas are there in 6.8 liters at standard temperature and pressure (273 k and 100 kpa)?

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0.3 moles

Explanation:-

According to the question,

Volume of nitrogen gas V = 6.8 litres.

Pressure of nitrogen gas P = 100 kPa.

Temperature of nitrogen gas T = 273 K.

We know the value of universal gas constant R = 8.314 litres kPa K−1 mol−1

Using the relation

PV = nRT

We have Number of moles of nitrogen gas n = P V / RT

= 100 kPa x 6.8 litres / ( 8.314 litres kPa K−1 mol−1 x 273 K)

= 0.3 mol

Thus there are 0.3 moles of nitrogen gas in 6.8 liters at standard temperature and pressure (273 K and 100 kPa)

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles