Two moles of gas a spontaneously convert to three moles of gas b in a container where the temperature and pressure are held constant. the sample originally took up 10.2 l of volume. what is the new volume of the products

2A >3B

from equation 2 mol 3 mol

Volumes of the gases under the same conditions are proportional to the numbers of the moles of these gases.

n(A) : n(B) = V(A) : V(B)

V(B) = n(B)*V(A)/n(A) = 3*10.2/2 = 15.3 L

V(B)=15.3 L

answer: they produce more slow than unicellular organisms.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol