How many grams are present in 7.2 mol of table salt, nacl?

-

421.2 g

Explanation: -

Atomic mass of Na = 23 g / mol

Atomic mass of Cl = 35.5 g / mol

Molar mass of NaCl = 23 x 1 + 35.5 x 1

= 58.5 g / mol

Number of moles of NaCl = 7.2 mol

Mass of NaCl = number of moles x molar mass

= 7.2 mol x 58.5 g/ mol

= 421.2 g

the correct answer is answer a. a mixture

no other options make sense

hope this

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  - sprinkles

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24