What the volume of the container needed to store 0.8 moles of argon gas at 5.3 atm and 227*c ( given r=0.08205lx atm/mol x k)

Hey There!:

227ºC in kelvin :

227 + 273.15 => 500.15 K

We use the Clapeyron equation :

p * V = n * R * T

5.3 * V = 0.8 * 0.08205 * 500.15

5.3 V = 32.829846

V = 32.829846 / 5.3

V = 6.194 L

hope this helps!

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explanation:

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