5grams of nahco3 was added to 50 cm3 of 1.5 mol dm-3 hydrochloric acid, causing the temperature to decrease by 6.8 k. what is the enthalpy of neutralization per mole of nahco3?

The chemical equation representing the neutralization reaction between HCl and is,

Given mass of = 5g

Moles of =

Volume of HCl solution =

Assuming the density of solution to be 1.0 g/mL

Mass of HCl solution = 50 g

Total mass of solution = 50 g+ 5 g = 55 g

Calculating the heat of neutralization:

Q = m C ΔT

m is mass of solution = 55 g

C is the specific heat capacity of the solution = 4.184

ΔT = Temperature difference = 6.8 K = (6.8 -273 ) C = -266.2

Enthalpy of neutralization per mole of

=

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