How much heat is required to raise the temperature of 100 grams of water from, 25c to 82 c?

- 23.8 kJ of heat is required to raise the temperature of water.

Solution:- We have been given with grams of water, it's initial and final temperature and asked to calculate the heat required to raise it's temperature. Here, lower degree C water is changing into higher degree C water. So, the formula used to calculate the heat is:

Where, q is the heat energy, m is mass, c is specific heat of water and delta T is change in temperature.

m = 100 grams

= 82 - 25 = 57 degree C

q=?

Let's plug in the values in the formula and do the calculations:

q = 23848.8 J or 23.8 kJ

So, 23.8 kJ of heat is required to raise the temperature of 100 g of water from 25 to 82 degree C.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)