If 6.00 g of carbon is burned completely, what volume of carbon dioxide gas is released at stp?
6.0 l
11.2 l
22.4 l
134.4 l

For this question, use the formula PV=nRT
firstly, define your knowns (this requires you to calculate moles of carbon)
P=101.3 kPa
V=?
n= 6.0/12 = 0.5
R= 8.31
T= 273 K
V= (0.5 x 8.31 x 273) / 101.3
   =11.19
therefore, 11.2 L of carbon dioxide will be produced 
NOTE: mole ratios were taken in to account, since there is one carbon in each CO2, the moles of carbon in the same matched the moles of CO2 produced in this instance