Calculate the molality of a solution formed by dissolving 27.8 g of lii in 500.0 ml of water.

Molarity of a solution : 0.416 M

In our question LiI(Lithium Iodide) is solute and we need to find the moles of LiI.

Given grams of LiI = 27.8g , Volume of solution = 500 mL

Molar mass of LiI = 133.85 g/mol

Moles of LiI = 0.208 mol

To find molarity we need volume of solution in 'L' , so we need to convert 500 mL to L.

1 L = 1000 mL

Volume = 0.5 L

Molarity = or 0.416 M

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explanation: