3.6 grams of boron react with 1.0 grams of hydrogen to give 4.6 grams of bh3. how many grams of boron would react with 3.3 grams of

The mass of boron that will react with 3.3 g of Hydrogen is 11.88 g

From the question given above, we were told that 3.6 g of boron react with 1.0 g of hydrogen to give 4.6 grams of BH3.

With the above information in mind, we can obtain the mass of boron needed to react with 3.3 g of hydrogen. This can be obtained as follow:

From the question given above,

3.6 g of boron react with 1.0 g of hydrogen

Therefore, Xg of boron will react with 3.3 g of Hydrogen i.e

Xg of boron = 3.6 × 3.3

Thus, we can conclude that 11.88 g of boron will react with 3.3 g of Hydrogen

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The hydrogen will react with 12 g B

Mass of B = 3.3 g H_2 × (3.6 g B/1.0 g H_2) = 12 g B

answer: a chemical reaction

explanation:

im not wrong

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.