Agas sample occupies 3.25 liters at 297.5k and 2.4 atm. determine the temperature at which the gas will occupy 4.25 l at 1.50 atm.

For equal moles of  gas, temperature can be calculated from ideal gas equation as follows:

P×V=n×R×T (1)

Initial volume, temperature and pressure of gas is 3.25 L, 297.5 K and 2.4 atm respectively.

2.4 atm ×3.25 L=n×R×297.5 K

Rearranging,

n\times R=0.0262 atm L/K

Similarly at final pressure and volume from equation (1),

1.5 atm ×4.25 L=n×R×T

Putting the value of n×R in above equation,

1.5 atm ×4.25 L=0.0262 (atm L/K)×T

Thus, T=243.32 K