What is the molarity of hcl found in a titration where 50 ml of hcl is titrated with 50 ml of .1 m naoh? needs to be answered asap rocky

0.1 mol/L . The concentration of the HCl is 0.1 mol/L

a)Write the balanced chemical equation

HCl + NaOH → NaCl + H2O

b)Calculate the moles of NaOH

Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)

= 0.0050 mol NaOH

c)Calculate the moles of HCl

Moles of HCl = 0.0050 mol NaOH x (1 mol HCl/1 mol NaOH)

= 0.0050 mol HCl

d)Calculate the molar concentration of the HCl

c = moles/litres = 0.0050 mol/0.050 L = 0.1 mol/L

43.452

step-by-step explanation:

284 times .153 = 43.452

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml