Lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% galena by mass. part a if the lead can be extracted with 92.5% efficiency, what mass of ore is required to make a lead sphere with a 8.00 cm radius?

The volume of sphere can be calculated using the following formula:

Here, r is radius of the sphere which is 8 cm. Putting the value,

This is equal to the volume of lead, density of lead is thus, mass of lead can be calculated as follows:

Let the mass of ore be 1 g, 68.5% of galena is obtained by mass, thus, mass of galena obtained will be 0.685 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.685×0.866=0.5932 g

Therefore, 0.5932 g of lead is obtained from 1 g of ore, if the efficiency is 100%.

For 92.5% efficiency, mass of lead obtained will be:

Thus, 1 g of lead obtain from grams of ore.

Thus, of lead obtain from:

Therefore, mass of ore required to make lead sphere is 44.2 kg.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)