When ammonium nitrate (nh4no3) explodes, the products are nitrogen, oxygen and water. when 40 grams of ammonium nitrate explode, 14 grams of nitrogen and 8 grams of oxygen form. how many grams of water form?

              18 g of H₂O

Solution:

The Balance Chemical Reaction is as follow,

                              2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation ,

              160 g (2 mole) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                       40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                      X =  (40 g × 72 g) ÷ 160 g

                      X  =  18 g of H₂O

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

Let's consider the balanced equation for the decomposition reaction of ammonium nitrate.

2 NH₄NO₃ → 2 N₂ + O₂ + 4 H₂O

According to Lavoisier's law of conservation of mass, the sum of the masses of the reactants must be equal to the sum of the masses of the products over a chemical reaction. The mass of water formed is:

When 40 g of ammonium nitrate explode, 14 g of nitrogen, 8 g of oxygen and 18 g of water are formed.

You can learn more about Lavoisier's law here:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied