Suppose 14 quarts of a solution that is 36% antifreeze is mixed with 6 quarts of a solution that is 12% antifreeze.

Missing question:

1. How many quarts of antifreeze are in the resulting mixture?

2. What % of the resulting mixture is antifreeze?

1) V₁ = 14 qt; volume of solution.

ω₁ = 36% ÷ 100% = 0.36.

V₂ = 6 qt.

ω₂ = 12% ÷ 100% = 0.12.

V₃ = V₁ · ω₁ + V₂ · ω₂.

V₃ = 14 qt · 0.36 + 6 qt · 0.12.

V₃ = 5.76 qt;  quarts of antifreeze in the resulting mixture.

2)  ω₃ = V₃ / (V₁ + V₂) · 100%.

ω₃ = 5.76 qt / (14 qt + 6 qt) · 100%.

ω₃ = 28.8 %; % of the resulting mixture is antifreeze.

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