What mass of lead (density 11.4 g/cm3) would have an identical volume to 28.5 g of mercury (density 13.6 g/cm3)?

The density of a material is its unique property which is different for different substances. The volume or mass of a compound can be determined from the other given mass of a compound, if the density of both the material is available. We know density of a material is equal to the mass per unit volume. From the given data 13.6 g of mercury has 1 cm³ volume. Thus 28.5g of mercury will have cm³ volume. Now as per the given density value of lead 11.4g of lead has 1 cm³ volume. Thus 2.095 cm³ volume of lead has (2.095×11.4)=23.889g.

h let me think

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j