If the lead can be extracted with 92.5% efficiency, what mass of ore is required to make a lead sphere with a 3.50 cm radius? lead metal can be extracted from a mineral called galena, which contains 86.6% lead by mass. a particular ore contains 68.5% galena by mass.

The volume of sphere can be calculated using the following formula:

Here, r is radius of the sphere which is 3.5 cm. Putting the value,

This is equal to the volume of lead, density of lead is thus, mass of lead can be calculated as follows:

m=d×V

Putting the values,

Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.

Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:

m=0.686×0.866=0.5940 g

Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency

1 g of lead obtain from grams of ore.

Thus, 2041.2 g of lead obtain from:

Therefore, mass of ore required to make lead sphere is 3.715 kg.

pure water does not conduct electricity very well. however, when certain substances are dissolved in water, the solution does conduct electricity. you can make a simple device that shows how well a solution conducts electricity. this device uses a flashlight bulb to indicate how well the solution conducts electricity. the better the solution conducts electricity, the brighter the bulb will glow.

explanation: