The solubility of lead (ii) carbonate is 2.7x10^-7 mol/l. what is its ksp?
the correct answer is 7.3x10^-14, but i keep getting 7.87x10^-20

First, the solubility product of PbCO₃ :

PbCO₃ ⇆ Pb⁺²   +   CO₃⁻²

Ksp = [ Pb⁺²] [ CO₃⁻² ]

Kps = ( 2.7x10⁻⁷) *  ( 2,7x10⁻⁷)  ---> multiplique, add the exponents and conserve sign

Kps = 7.3x10⁻¹⁴

hope this helps!

The kinetic energy of the liquid increases. hope this !

D. most models represent a real world object in a simpler way