A50.0-g sample of liquid water at 25.0 °c is mixed with 35.0 g of water at 51.0 °c. the final temperature of the water is °c.

[text]Solution:\\ Heat blance is gained by 50g =Heat balance lost by 25g of water\\ So,\\ \(M1 \times temp + M2 \times temp/M1+M2)frac{(50.0g\times25.0^{.}c)+(23.0g\times57.0^{.}c)}{50.0g+23.0g}         =35.1^{.}c}[/tex]

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.