Nicotine, a component of tobacco, is composed of c, h, and n. a 2.625-mg sample of nicotine was combusted, producing 7.1210 mg of co2 and 2.042 mg of h2o. what is the empirical formula for nicotine?

The mass sample of nicotine combusted = 2.625 mg  (given)

Mass of produced = 7.1210 mg  (given)

Mass of produced = 2.042 mg  (given)

Molar mass of = 44 g/mol

Molar mass of = 18 g/mol

Percentage of Carbon = %

Percentage of hydrogen = %

Now, for percentage of nitrogen = %

Calculating the moles of each element:

Dividing with the smallest mole value to calculate the molar ratio of each element:

Hence, the empirical formula for nicotine is .

solute : a solute is a substance that is dissolved in another substance is known as a solvent. it is mixed with a special mixture know as homogeneous mixture.

solvent: a solvent is a substance that dissolved a solute, which results in a solution is known as solvent.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.