If a chemist wishes to dilute a 1.000 x 103 mg/l stock solution to prepare 5.000 x 102 ml of a working standard that has a concentration of 6.250 mg/l, what volume of the 1.000 x 103 mg/l standard solution is needed?

Given data:

Concentration of stock solution which is the initial solution = M1 = 1.00 * 10^3 mg/L

Concentration of prepared solution i.e final solution = M2 = 6.250 mg/L

Volume of final solution, V2 = 5.000 * 10^2 ml

To determine:

The initial volume i.e. volume of the stock solution required = V1

Calculation:

Use the relation

M1V1 = M2V2

V1 = M2V2/M1 = 6.250 mg.L-1 * 5.000*10^2 ml/1.00 * 10^3 mg.L-1

V1 = 3.125 *10^3 ml

The volume of stock solution required is 3.125 *10^3 ml

the answer would be a

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.