Marcia has 2 liters of a 60% concentrated solution of phosphoric acid. she wants to add 3 liters of less concentrated phosphoric acid solutions, so that she has 5 liters of a solution with a concentration less than 50%. which could she add? indicate all possible combinations of solutions.

initial concentration = 60%

initial volume = 2 L

Final volume = 5 L

Final concentration required = Less than 50%

This is possible if we add a less concentrated solution of say concentration x%

5X (50) = 2 X 60 + 3 (x)

x = 43.33

So we have to add 3 L of solution with concentration less than 43.33%

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole